Portable Freeware Development • regex case conversion in dropit

hi
i'm beginner for regular expression and i hope help for that question: the syntax of the regex inside dropit is:

regex (p1, r1)

p1 = regex pattern
r1 = regex replacement pattern

the regex that I have created is made this way

regex(\d?\dx\d\d \p{Ll},)

I would want to convert the lowercase character (\p{Ll}) in uppercase and to leave the other as it is
I don't succeed in understanding as he does, I don't succeed in returning the same regex of origin converting only the lowercase character after the space in uppercase

What is the syntax for the regex replacement pattern?

thanks

Statistics: Posted by progser — Sun Dec 09, 2018 2:50 am

---